A boat moves through the water with two
forces acting on it. One is a 2000 N forward
push by the motor on the propeller, and the
other is an 1741 N resistive force due to the water around the bow.
What is the acceleration of the 1020 kg
boat?
Answer in units of m/s2
Fn = F1 - F2 = 2000 - 1741 = 259N. = Net force.
F = ma,
a = Fn / m = 259 / 1020 = 0.254m/s^2.
To find the acceleration of the boat, we can use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass.
In this case, the net force acting on the boat is the forward push by the motor minus the resistive force due to the water:
Net force = Forward push - Resistive force
= 2000 N - 1741 N
= 259 N
Now, we can calculate the acceleration using Newton's second law:
Acceleration = Net force / Mass
= 259 N / 1020 kg
Dividing the net force (259 N) by the mass of the boat (1020 kg), we get:
Acceleration ≈ 0.254 m/s²
Therefore, the acceleration of the boat is approximately 0.254 m/s².