Algebra

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The distance required for an emergency stop for a car varies directly as the square of the car’s speed. A car traveling at 50 mph requires 140 feet to stop. What is the stopping distance for a car traveling at 30 mph? What is the stopping distance for a car traveling at 70 mph?

  • Algebra -

    You are told that

    d(v) = kv^2

    140 = k*2500
    k = 0.056

    so,
    d(30) = .056*900
    d(70) = .056*4900

  • Algebra -

    THANK YOU!

  • Algebra -

    350

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