posted by Anonymous .
During a baseball game, a batter hits a popup to a ﬁelder 81 m away.
The acceleration of gravity is 9.8 m/s
If the ball remains in the air for 6.7 s, how
high does it rise?
It rises the same distance that an object will fall in 6.7/2 = 3.35 seconds, because that is the time that it will take the ball to fall from maximum height.
H = (1/2)*g*(3.35)^2