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During a baseball game, a batter hits a popup to a fielder 81 m away.
The acceleration of gravity is 9.8 m/s
If the ball remains in the air for 6.7 s, how
high does it rise?

  • physics -

    It rises the same distance that an object will fall in 6.7/2 = 3.35 seconds, because that is the time that it will take the ball to fall from maximum height.

    H = (1/2)*g*(3.35)^2

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