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A baseball player hits a baseball into the outfield. The equation h= -0.005x^2 +x+3 give the path of the ball, where (h) is the height and (x) is the horizontal distance the ball travels.

A. What is the equation of the axis of symmetry? It's -100 right?
B. What is the Mac height reached by the baseball? Idk
C. An outfielder catches the ball 3 ft above the ground. How far has the ball traveled horizontally when the outfielder catches it? Idk

• Alg 1 quadratic functions -

Y = -0.005x^2 + x + 3

A. h = Xv = -b / 2a = -1 / -0.01 = 100 X = 100 = Eq of axis of symmetry.

B. The max ht = Y-coordinate of vertex.
In the given Eq, substitute 100 for X
and get: Yv = K = 53 = max ht.

V(h,k) = V(100,53).

C. Y = -0.005x^2 + x + 3 = 3,
-0.005x^2 + x = 3-3 = 0,
x(-0.005x + 1) = 0,

X = 0,
-0.005x + 1 = 0,
0.005x = 1,
X = 200 = Hor. distance traveled.

• Alg 1 quadratic functions -

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