Math
posted by HELP ME PLEASEEEE .
The marching band, cheerleaders, and chaperones are traveling by bus to play in the Citrus Bowl parade in Orlando. There are 216 bank members, 32 cheerleaders, and 40 chaperones making the trip. They can rent any number of one type of bus shown in the charter below.
BUSES AVAILABLE FOR RENT
Number of Passangers 20 32 44
Cost per Day $200 $265 $400
What is the least amount they must spend for everyone to travel to the Citrus Bowl? You have four options:
f)$1,855; g)$2,385; h)$2,800; i)$3,000
Can you please give me the answer and explain the procedure. Thank you very much for your help.

First, divide the total number, 288, by the number of passengers each bus can carry. Remember that you can't rent a part of a bus.
Then multiply each cost by the number of buses needed.
I'll be glad to check your answer. 
Bus No 1 : 20 people for 200
for 298 people = 298/20 = 14.9 ~ 15
15 * 200 = $3000
Bus No 2 : 32 people for 265
for 298 people = 298/32 = 9.3 ~ 10
10 * 265 = $2650
Bus No 3 : 44 people for 400
for 298 people = 298/44 = 6.7 ~ 7
7 * 400 = $2800
It seems like that one of the option is missing which is 2650 and smallest amount of all mentioned. Hope this helps. 
I didn't get the same answer as John Smith.
Only 288 people are traveling, not 298. 
Bus No 1 : 20 people for 200
for 288 people = 288/20 = 14.4 ~ 15
15 * 200 = $3000
Bus No 2 : 32 people for 265
for 288 people = 288/32 = 9
9 * 265 = $2385
Bus No 3 : 44 people for 400
for 288 people = 288/44 = 6.5 ~ 7
7 * 400 = $2800
Sorry got it wrong last time. but its ok now. Option g is correct answer
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