Suppose the fame of a gas burner stove emits light just like a blackbody. The flame appears blue,emiting most of its light at a wave lengh of 475nanometers. what is the temperature of the flame? How do I solve this?
To determine the temperature of the gas burner stove flame, you can use Wien's displacement law.
Wien's displacement law states that the peak wavelength of the emitted radiation from a blackbody is inversely proportional to its temperature. The formula for Wien's law is:
λmax = (b / T)
Where:
- λmax is the peak wavelength of the emitted radiation
- b is Wien's constant, equal to approximately 2.898 x 10^-3 m·K
- T is the temperature of the gas burner stove flame in Kelvin
To solve for the temperature (T), rearrange the formula:
T = b / λmax
Substituting the given peak wavelength of 475 nanometers (475 x 10^-9 m) into the equation:
T = (2.898 x 10^-3 m·K) / (475 x 10^-9 m)
Calculate the result:
T ≈ 6100 K
Therefore, the temperature of the gas burner stove flame is approximately 6100 Kelvin.