a ball of mass 3 kg is moving with a velocity of 10 m/s. This ball collides with a second ball of mass 0.5 kg that is at rest. After the collison, the first ball is at rest. What is the velocity after the collison of the second ball if the collison is inelastic?
Inelastic collisions do not conserve kinetic energy, but they do conserve momentum.
3*10 + .5*0 = 3*0 + .5*v
30 = .5v
v = 60 m/s
M1v1 +M1v1=(m1+m2)v (3*10) + (0.5*0)=(3+0.5)v 30 + 0 = 3.5v 30 =3.5v v =8.57m/s.
To find the velocity of the second ball after the collision, we can use the principle of conservation of momentum. In an inelastic collision, the two objects stick together and move as one.
The conservation of momentum states that the total momentum before the collision is equal to the total momentum after the collision.
Before the collision, the first ball has a mass of 3 kg and a velocity of 10 m/s, while the second ball has a mass of 0.5 kg and is at rest. Hence, the total momentum before the collision is:
Total momentum before = (mass of first ball * velocity of first ball) + (mass of second ball * velocity of second ball)
= (3 kg * 10 m/s) + (0.5 kg * 0 m/s)
= 30 kg m/s
After the collision, the first ball is at rest. Therefore, its velocity is 0 m/s. Let's denote the velocity of the second ball after the collision as V2.
Total momentum after = (mass of first ball * velocity of first ball) + (mass of second ball * velocity of second ball)
= (3 kg * 0 m/s) + (0.5 kg * V2)
According to the principle of conservation of momentum:
Total momentum before = Total momentum after
30 kg m/s = (3 kg * 0 m/s) + (0.5 kg * V2)
Simplifying the equation, we have:
30 kg m/s = 0 kg m/s + (0.5 kg * V2)
30 kg m/s = 0.5 kg * V2
Dividing both sides of the equation by 0.5 kg, we find:
V2 = (30 kg m/s) / 0.5 kg
V2 = 60 m/s
Therefore, the velocity of the second ball after the collision is 60 m/s.