MATH (PLease HELp)
posted by Tiffany .
Sally has three times as many dimes as nickels and twice as many quarters as dimes.In all she has $5.55. How many coins of each type does she have?
Let 2x=quarters
3x=dimes
x=nickles < is that correct please help put

i think the answer is
3 nickels .15
9 dimes .90
18 quarters 4.50
total 5.50 
It's easy enough to check.
The numbers add up, and the values add up.
You added wrong at the very end. 4.50 + .90 + .15 does indeed make 5.55
However, your equations do not represent the facts:
x = nickels
3x = dimes
2(3x) = 6x = quarters
5x + 10(3x) + 25(6x) = 555
185x = 555
x=3 
Megan has three times as many quarters than nickels. She has one less dime than the number of quarters. If she has a total of $4.30, how many of each coin does she have ?

Nickels = x
Quarters = 3x
Dimes = 3x1
Plug in equation with coin values in ()...
(5)x + (25)3x + (10)3x1 = 430
5x + 75x + 30x  10 = 430
80x + 30x  10 = 430
110x 10 = 430
110x 10 +10 = 430 + 10
110x = 440
x = 4
Nickels = 4 (x)
Quarters = 12 (3x)
Dimes = 11 (3x1)
4x5=20 N
12x25=300 Q
11x10=110 D /
/
20+300+110= 430 cents \/