PHYSICS
posted by HELPPPPPPP .
A ROCK IS THROWN OFF A CLIFF WITH AN HORIZONTAL VELOCITY OF 55.0 M/SEC. IT TAKES THE ROCK 7.0 SEC TO HIT THE GROUND
A)WHAT IS THE HEIGHT OF THE CLIFF
B) HOW FAR FROM THE FOOT OF THE CLIFF DOES THE ROCK HIT THE GROUND
C)WHAT IS THE HORIZONTAL COMPONENT OF VELOCITY WITH WHICH HITS THE GROUND
D) WHAT IS THE VERTICAL COMPONENT OF VELOCITY WITH WHICH IT HITS THE GROUND

A. h = Vo*t + 0.5g*t^2,
h = 0 + 4.9*7^2 = 240m.
B. d = VT = 55m/s * 7s = 385m.
C. Vh = Vo + at = 55 + 0*7 = 55m/s.
D. Vv = Vo + gt = 0 + 9.8*7 = 68.6m/s.
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