A man tries to pull out a nail on the wall with a string attached to the head of the nail and pull at an angle of 30 degree to the wall if the tension in the string is 15N. Calculate the force effective pulling out the nail.
Wmda
To calculate the effective force pulling out the nail, we need to consider the forces acting on the nail and the angle at which the man is pulling.
First, let's label the forces involved:
1. Tension force (T): This is the force exerted by the string pulling the nail.
2. Effective force (F): This is the force pulling the nail out of the wall.
3. Normal force (N): This is the force exerted by the wall on the nail, perpendicular to the surface of the wall.
4. Friction force (Ff): This is the force opposing the motion of the nail out of the wall.
From the given information, we have:
Tension force (T) = 15 N
Angle with the wall (θ) = 30 degrees
To find the effective force (F), we need to resolve the tension force (T) into its horizontal and vertical components.
The horizontal component of the tension force (Tcosθ) is equal to the friction force (Ff). Since the nail is being pulled to overcome the friction, we assume the friction force is at its maximum value. Therefore, Ff = Tcosθ.
The vertical component of the tension force (Tsinθ) is balanced by the normal force (N) exerted by the wall.
Now, to calculate the effective force (F), we only need to consider the horizontal component of the tension force (Tcosθ).
Thus, the effective force (F) = Tcosθ.
Now let's substitute the given values into the equation:
F = Tcosθ
F = 15 N * cos(30°)
F ≈ 13.0 N
Therefore, the effective force pulling out the nail is approximately 13.0 Newtons.