the coach wants to introduce each of the starting players at tuesday's game. in how many different orders can each of the 5 starting players be introduced?
120 bro
To find the number of different orders in which the 5 starting players can be introduced, we can use the concept of permutations.
In permutations, the order matters, and no item can be repeated once it has been used.
For the first player, we have 5 options. Once the first player is chosen, we have 4 options for the second player. For the third player, we have 3 options remaining, and so on.
So, to calculate the total number of different orders, we multiply the number of options for each player together:
5 * 4 * 3 * 2 * 1 = 120
Therefore, there are 120 different orders in which the 5 starting players can be introduced.
To determine the number of different orders in which the 5 starting players can be introduced, we need to consider the concept of permutations.
A permutation is an arrangement of objects in a particular order. In this case, we have 5 starting players to be introduced, which means we need to find the number of permutations of these 5 players.
The formula to calculate permutations is given by:
P(n, r) = n! / (n-r)!
Where:
P(n, r) stands for the number of permutations of n objects taken r at a time,
n! represents the factorial of n (n factorial),
and (n-r)! represents the factorial of (n-r).
Using this formula, we can calculate the number of permutations for our case:
P(5, 5) = 5! / (5-5)!
= 5! / 0!
= 5! / 1
= 5 x 4 x 3 x 2 x 1 / 1
= 5 x 4 x 3 x 2
= 120
Therefore, there are 120 different orders in which the 5 starting players can be introduced at Tuesday's game.