calculus
posted by Eric .
Consider the function y=x/(x+1)
a) Find dy/dx
b) Find the equation of the line tangent to the curve at x=2
c) Find the equation of the line normal to the curve at x=1

dy/dx = [(x+1)1 x(1) ] / (x+1)^2
= 1/(x+1)^2
at x = 2
y = 2/1 = 2 so through point (2,2)
dy/dx = m = 1/1 = 1
so
y = 1 x + b
2 = 2 + b
b = 4
y = x +
for part c
find a new m at x = 1, y = 1/2
the m we want = 1/m
then repeat method of part b
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