posted by Colin .
A solution of .12 L of 0.160 M KOH is mixed with a solution of .3 L of 0.230 M NiSO4.
the equation for this reaction is:
2KOH (aq)+NiSO4 (aq) ----->K2SO4 (aq)+Ni(OH)2 (s)
.89 grams of Ni(OH)2 precipitate form
I need to know the concentration remaining in the solution of:
1) Ni (II)
I do not know how to do these nor can i find aid to show me how to do it step by step, so to whoever answers this question, could you also show steps so i can learn how to do this? thank you to whoever puts in their time and helps me!!
See your other post above.