The sum of two consecutive even integers is 118.
A. Define a variable for the smaller integer.
B. What must you add to an even integer to get the next greater even integer?
C. Write an expression for the second integer.
D. Write and solve an equation to find the two even integers.
small = s
add 2 to get the next even number
large = s+2
s + s+2 = 118
2s + 2 = 118
2s = 116
s = 58
the two even numbers are 58, 60
the sum of three consecutive integers is -30
A. Let's define a variable for the smaller integer as "x".
B. To get the next greater even integer, we need to add 2 to any even integer.
C. The expression for the second integer would be "x + 2".
D. Now, let's write and solve an equation to find the two even integers.
We know that the sum of the two consecutive even integers is 118. So, we can write the equation as:
x + (x + 2) = 118
Simplifying the equation:
2x + 2 = 118
Subtracting 2 from both sides:
2x = 116
Dividing both sides by 2:
x = 58
Therefore, the smaller even integer is 58, and the second even integer is 58 + 2 = 60.
A. Let's define a variable for the smaller integer. Let's call it "x."
B. To get the next greater even integer, you need to add 2 to the current even integer. This is because consecutive even integers have a difference of 2. So, by adding 2 to an even integer, you will get the next greater even integer.
C. The expression for the second integer would be x + 2. Since we defined the smaller integer as "x," adding 2 to it gives us the second integer.
D. To find the two even integers, we need to set up an equation based on the given information. The sum of the two consecutive even integers is 118, so we can write an equation as:
x + (x + 2) = 118
Now, we can solve this equation to find the values of x and the second integer.
Combining like terms:
2x + 2 = 118
Subtracting 2 from both sides:
2x = 116
Dividing both sides by 2:
x = 58
So, the smaller even integer (x) is 58, and the second even integer (x + 2) is:
58 + 2 = 60
Therefore, the two even integers are 58 and 60.