Determine the mass of KHP (molar mas = 204.2 g/mol) that is required to react with 30.0 mL of 1.0 M Na0H (molar mass 40.0 g/mol)if the reaction is NaOH + KHP --> NaKP + H2O
To determine the mass of KHP required to react with 30.0 mL of 1.0 M NaOH, we need to follow these steps:
Step 1: Convert the given volume of NaOH to moles.
To do this, we need to use the molarity of NaOH (1.0 M) and the volume (30.0 mL). First, convert the volume to liters:
30.0 mL = 30.0 mL x (1 L / 1000 mL) = 0.0300 L
Now, multiply the volume by the molarity to find the number of moles of NaOH:
Number of moles = Volume (in L) x Molarity
Number of moles = 0.0300 L x 1.0 mol/L = 0.0300 mol
Step 2: Determine the mole ratio between NaOH and KHP.
From the balanced equation, we can see that the molar ratio between NaOH and KHP is 1:1. This means that for every 1 mole of NaOH, we need 1 mole of KHP.
Step 3: Calculate the mass of KHP needed.
The molar mass of KHP is given as 204.2 g/mol. Since we have the number of moles required from step 2 (which is also 0.0300 mol), we can use the formula below to calculate the mass:
Mass = Number of moles x Molar mass
Mass = 0.0300 mol x 204.2 g/mol = 6.126 g
Therefore, the mass of KHP required to react with 30.0 mL of 1.0 M NaOH is 6.126 grams.