How do i factor
16w^6-2q^6
I think the answer is
2(2w^2-q^2)(4w^4+2w^2q^2+q^4)
good job
You Mean this is right?
WOW I DID IT
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To factor the expression 16w^6 - 2q^6, we can use the difference of squares formula. The formula states that a^2 - b^2 can be factored as (a + b)(a - b).
In this case, let's rewrite the expression as (4w^3)^2 - (√2q^3)^2, where we have separated the terms as perfect squares.
Applying the difference of squares formula, we can factor the expression as follows:
16w^6 - 2q^6 = (4w^3 + √2q^3)(4w^3 - √2q^3)
Therefore, the factored form of 16w^6 - 2q^6 is (4w^3 + √2q^3)(4w^3 - √2q^3).