# algebra 1b

posted by sam

Use the table below to find the products of the two polynomials. Enter your answer in descending order in the box below. Enter exponents using the caret ( ^ ). For example, you would enter as 4x^2. Do not enter spaces in your answer.

(x3 + 2x2 - 2)(x3 - 3x + 3)how do you do this?

1. Steve

Just multiply term by term, just as you do with a multi-digit number:

124* 327 = 100(300+20+7) + 20(300+20+7) + 4(300+20+7)

(x^3 + 2x^2 - 2)(x^3 - 3x + 3)
= x^3(x^3 - 3x + 3) + 2x^2(x^3 - 3x + 3) - 2(x^3 - 3x + 3)

= x^6 - 3x^4 + 3x^3 + 2x^5 - 6x^3 + 6x^2 - 2x^3 + 6x - 6

= x^6 + 2x^5 - 3x^4 - 5x^3 + 6x^2 + 12x - 6

2. Steve

Ahem. Make that + 6x

3. sam

thanks :)

4. sam

(x7 + x4 + x)(x3 - 1)
can u help me with this one 2

5. sam

it was wrong the first one

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