algebra 1b
posted by sam
Use the table below to find the products of the two polynomials. Enter your answer in descending order in the box below. Enter exponents using the caret ( ^ ). For example, you would enter as 4x^2. Do not enter spaces in your answer.
(x3 + 2x2  2)(x3  3x + 3)how do you do this?

Steve
Just multiply term by term, just as you do with a multidigit number:
124* 327 = 100(300+20+7) + 20(300+20+7) + 4(300+20+7)
(x^3 + 2x^2  2)(x^3  3x + 3)
= x^3(x^3  3x + 3) + 2x^2(x^3  3x + 3)  2(x^3  3x + 3)
= x^6  3x^4 + 3x^3 + 2x^5  6x^3 + 6x^2  2x^3 + 6x  6
= x^6 + 2x^5  3x^4  5x^3 + 6x^2 + 12x  6 
Steve
Ahem. Make that + 6x

sam
thanks :)

sam
(x7 + x4 + x)(x3  1)
can u help me with this one 2 
sam
it was wrong the first one
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