Algebra-HELP

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Find the x and y intercepts of f(x)=x^2-x-6.

• Algebra-HELP -

y=f(x)=x^2-x-6

The y-intercept is the value of y when x=0.
Substitute x=0 in the above equation to find the y-intercept.

The x-intercept is to find the roots of the equation, when y=0, or
f(x)=x^2-x-6=0
By factoring f(x) into
f(x)=(x-3)(x+2)
you should be able readily find the two zeroes of f(x).
If you need further help, post again.

• Algebra-HELP -

well i know the x-intercept is (3,-2)
but i can seem to understand y intercept. I thought it would be (0,0) but it was wrong

• Algebra-HELP -

The y-intercept is where the graph crosses the y-axis, that is, where x=0.

In this case, f(0) = 0 - 0 - 6 = -6, so the y-intercept is (0,-6)

• Algebra-HELP -

Also, there are two x-intercepts: (3,0) and (-2,0). They are the points where the graph crosses the x-axis, not just the x-values.

• Algebra-HELP -

Thank you!!

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