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N2 (g) + 3H2 (g) → 2NH3 (g)ΔH = -92.6 Calculate ΔH (in kJ) for the decomposition of 30.5 g NH3 (g) into N2 (g) and H2 (g)

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    For the reverse reaction, DH = +92.6 (what), is it kJ? If so, then
    92.6 kJ x (30.5g/34.0g) = ?

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