you have a square wiht an 8-inch side. you want to draw a triangle with a base 3 times greater that a side of the square. what is the altitude of the triangle?
who cares? Nothing was said about what the height should be. As long as the base is 24, that works.
Do you want a triangle with the same area as the square, and equilateral triangle, or what?
the school cares and the question say the triangle with a base 3 times greater than the sides of the square
To find the altitude of the triangle, we can use the formula for the area of a triangle:
Area = (base * altitude) / 2
Given that the base of the triangle is 3 times greater than a side of the square, which has a length of 8 inches, the base of the triangle would be 3 * 8 = 24 inches.
Let's substitute the values into the formula:
Area = (24 * altitude) / 2
Since we don't have the area of the triangle, we can't directly solve for the altitude. However, we can work with the given information and use the properties of similar triangles to find the altitude.
Since the triangle is drawn on the square, we can notice that the triangle's height (altitude) is equal to the square's side length, which is 8 inches.
Therefore, the altitude of the triangle would be 8 inches.