What is the molarity (M) of a 627 mL solution that contains 12.7 g of ethanol, CH3CH2OH?
Well, let's calculate it! To find the molarity, we need to know the number of moles of ethanol (CH3CH2OH) in the solution.
First, we convert the mass of ethanol from grams to moles. The molar mass of ethanol is approximately 46.07 g/mol.
Moles = Mass / Molar mass
Moles = 12.7 g / 46.07 g/mol
Moles ≈ 0.2759 mol
Next, we need to convert the volume of the solution from milliliters to liters.
Volume = 627 mL = 0.627 L
Finally, we can calculate the molarity using the formula:
Molarity = Moles / Volume
Molarity = 0.2759 mol / 0.627 L
Molarity ≈ 0.440 M
So, the molarity of the 627 mL solution containing 12.7 g of ethanol is approximately 0.440 M.
Now that we've got the serious answer out of the way, let me tell you a funny ethanol joke:
Why did the ethanol go to a party?
Because it was a MOLEcular mixER! Cheers! 🍻
To find the molarity (M) of a solution, we need to know the number of moles of solute (ethanol, CH3CH2OH) and the volume of the solution.
Step 1: Calculate the number of moles of ethanol:
We can use the formula: moles = mass / molar mass
The molar mass of ethanol (CH3CH2OH) can be calculated by adding up the atomic masses of its elements:
C: 12.01 g/mol
H: 1.01 g/mol (there are 6 hydrogen atoms)
O: 16.00 g/mol
So the molar mass of ethanol is:
12.01 g/mol (C) + 1.01 g/mol (H) x 6 + 16.00 g/mol (O) = 46.07 g/mol
Using this molar mass, we can calculate the number of moles of ethanol:
moles = 12.7 g / 46.07 g/mol ≈ 0.2756 mol
Step 2: Convert the volume of the solution to liters:
The volume given is 627 mL. To convert it to liters, we divide by 1000 (1 L = 1000 mL):
Volume = 627 mL / 1000 mL/L = 0.627 L
Step 3: Calculate the molarity:
Molarity = moles / volume
Molarity = 0.2756 mol / 0.627 L ≈ 0.439 M
Therefore, the molarity of the solution is approximately 0.439 M.
To find the molarity (M) of a solution, you need to know the amount of solute in moles and the volume of the solution in liters.
First, let's find the amount of ethanol in moles. To do this, we need to know the molar mass of ethanol, which is the sum of the atomic masses of the atoms in its chemical formula: C2H6O.
C = 12.01 g/mol
H = 1.01 g/mol (there are 6 hydrogen atoms in ethanol)
O = 16.00 g/mol
Molar mass of ethanol = (2 * 12.01) + (6 * 1.01) + 16.00 = 46.07 g/mol
Now, we can calculate the amount of ethanol in moles by dividing the mass of ethanol by its molar mass:
Moles of ethanol = mass of ethanol / molar mass of ethanol
= 12.7 g / 46.07 g/mol
= 0.2757 mol
Next, we need to convert the volume of the solution from milliliters to liters. There are 1000 milliliters in 1 liter, so:
Volume of solution in liters = 627 mL / 1000 mL/L
= 0.627 L
Finally, we can calculate the molarity of the solution by dividing the moles of ethanol by the volume of the solution in liters:
Molarity (M) = moles of ethanol / volume of solution (in liters)
= 0.2757 mol / 0.627 L
≈ 0.439 M
Therefore, the molarity of the 627 mL solution that contains 12.7 g of ethanol is approximately 0.439 M.