Silver chloride decomposes in light to produce silver and chlorine.

What mass of silver is produced when 25g of silver chloride completely decomposes?
What volume of chlorine is produced at STP?

To determine the mass of silver produced when silver chloride decomposes, we need to first calculate the molar mass of silver chloride (AgCl).

The molar mass of silver (Ag) is 107.87 g/mol, and the molar mass of chlorine (Cl) is 35.45 g/mol.

So, the molar mass of silver chloride (AgCl) is:
Molar mass (AgCl) = Molar mass (Ag) + Molar mass (Cl)
= 107.87 g/mol + 35.45 g/mol
= 143.32 g/mol

Now we can calculate the number of moles of silver chloride in 25g using the formula:
Number of moles = Mass / Molar mass

Number of moles of silver chloride = 25g / 143.32 g/mol
= 0.1746 mol

According to the balanced equation, 1 mole of silver chloride produces 1 mole of silver.

Therefore, the number of moles of silver produced = 0.1746 mol.

To calculate the mass of silver produced, we can use the molar mass of silver (107.87 g/mol):
Mass of silver = Number of moles x Molar mass
= 0.1746 mol x 107.87 g/mol
= 19.01 g

So, when 25g of silver chloride completely decomposes, approximately 19.01g of silver is produced.

Now, let's determine the volume of chlorine gas produced at STP (Standard Temperature and Pressure).

STP conditions are defined as 0 degrees Celsius (273.15 K) and 1 atmosphere (1 atm) pressure.

At STP, 1 mole of any ideal gas occupies a volume of 22.4 liters.

The balanced equation tells us that 1 mole of silver chloride (AgCl) produces 1 mole of chlorine (Cl2).

So, the number of moles of chlorine produced is also equal to 0.1746 mol.

To calculate the volume of chlorine gas produced, we use the formula:
Volume = Number of moles x Molar volume

Volume of chlorine = 0.1746 mol x 22.4 L/mol
= 3.91 L

Therefore, approximately 3.91 liters of chlorine gas is produced at STP when 25g of silver chloride completely decomposes.