how much MgCl2 would you use to make 200mL of a 100mM solution of MgCl2
1.90g of MgCl2
To calculate the amount of MgCl2 required to make a 100mM solution in 200mL, we need to know the molar mass of MgCl2.
The molar mass of MgCl2 is:
Mg (24.31 g/mol) + 2Cl (35.45 g/mol) = 95.29 g/mol
Now, let's calculate the amount of MgCl2 needed.
First, convert the desired concentration (100mM) to moles per liter:
100 mM = 100 mmol/L
Since we want a final volume of 200 mL, we need to convert it to liters:
200 mL = 200/1000 L = 0.2 L
Now, using the molar mass and the desired concentration, we can calculate the amount of MgCl2 needed:
Amount (in moles) = concentration (in mol/L) * volume (in L)
Amount (in moles) = 100 mmol/L * 0.2 L = 20 mmol
Finally, let's convert the amount from moles to grams using the molar mass of MgCl2:
Mass (in grams) = amount (in moles) * molar mass (in g/mol)
Mass (in grams) = 20 mmol * 95.29 g/mol = 1905.8 mg
Therefore, you would need 1905.8 mg (or approximately 1.91 grams) of MgCl2 to make a 100mM solution in 200mL.
To determine how much MgCl2 to use, we need to consider the molar mass of MgCl2 and the desired concentration of the solution.
The molar mass of MgCl2 is 95.211 grams/mole.
Step 1: Convert the desired concentration from millimoles per liter (mM) to moles per liter (M).
100 mM = 100 mmol/L = 0.1 mol/L
Step 2: Convert the volume from milliliters to liters.
200 mL = 0.2 L
Step 3: Calculate the amount of MgCl2 needed using the formula:
Amount (moles) = concentration (M) × volume (L)
Amount (moles) = 0.1 mol/L × 0.2 L = 0.02 moles
Step 4: Convert moles to grams using the molar mass of MgCl2.
Weight (grams) = moles × molar mass
Weight (grams) = 0.02 mol × 95.211 g/mol = 1.90422 grams
So, you would need approximately 1.904 grams of MgCl2 to make 200 mL of a 100 mM solution of MgCl2.