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College Physics

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A students stands at the top of a high vertical cliff and throws calculators into the sea. He throws the calculators horizontally with a speed of 7.4 m/s and observes that each reaches the water below 3.7 s after the release. Neglect air resistance and find
(a) How far from the base of the cliff do the calculators strike he water?
(b) How high is the cliff?

  • College Physics -

    Hi,
    Since there is no acceleration in the horizontal direction the calculators would travel a dstance of
    (horizontal velocity)X (time of flight)
    =27.38
    to find the height of the cliff use
    D=v0t+1/2AT^2, since there is no initial velcity in the vertical direction cancel to get
    D=1/2AT^2 which = 67.081
    have fun!

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