algebra

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height of a projectile thrown straight up from top of 480 ft hill t seconds after bing thrown up with initial velocity vo ft/s is
h = -16t^2 +vot + 480

If vo = 96, find times when the projectile will be at a) height of 592 ft above the ground and b) crash on the ground.

  • algebra -

    so h = -16t^2 + 96t + 480

    a)
    you want
    -16t^2 + 96t + 480 = 592
    t^2 - 6t + 7 = 0
    (t-7)(t+1) =0
    t = 7 or a negative

    b)
    same thing except now you want
    -16t^2 + 96t + 480 = 0

    solve for t, use only the positive result

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