what is the net force needed to lift a full grocery sack weighing 210N uniformly?

Uniformly or not, it equals 210 N. I do not understand what the word "uniformly" adds to your question. Does it mean "at constant speed"?

F(lift)=F(weight) if uniformly.....the answer 210N

To determine the net force needed to lift a full grocery sack weighing 210N uniformly, we need to consider the force of gravity acting on the sack and the force applied to lift it.

The force of gravity, also known as the weight of the sack, is given as 210N.

To lift the sack uniformly, we need to overcome this force by applying an equal and opposite force in the upward direction. According to Newton's second law of motion, the net force is the mass of the object multiplied by the acceleration.

First, we can convert the weight of the sack (210N) to its mass by dividing it by the acceleration due to gravity. The acceleration due to gravity is approximately 9.8 m/s^2.

Mass = Weight / Acceleration due to gravity
Mass = 210N / 9.8 m/s^2 ≈ 21.43 kg

Since the acceleration is zero (assuming the sack is lifted with a constant velocity), the net force needed to lift the grocery sack is equal to its weight:

Net Force = Weight = 210N

Therefore, the net force required to lift the full grocery sack weighing 210N uniformly is 210N.

To calculate the net force needed to lift a full grocery sack weighing 210N uniformly, we need to consider the force of gravity acting on the sack. The force of gravity is the weight of the object and is given by the equation:

Force of gravity = mass x gravitational acceleration

In this case, the weight (force of gravity) is already given as 210N. The gravitational acceleration on Earth is approximately 9.8 m/s^2.

Hence, we can modify the equation to solve for the mass of the grocery sack:

Weight = mass x gravitational acceleration

Rearranging the equation:

mass = weight / gravitational acceleration

Substituting the given values:

mass = 210N / 9.8 m/s^2

mass ≈ 21.43 kg

Now that we know the mass of the grocery sack, we can determine the net force needed to lift it. When lifting an object, we need to overcome the force of gravity acting on it. Therefore, the net force required will be equal to the weight (force of gravity) of the grocery sack.

Hence, the net force needed to lift the full grocery sack weighing 210N uniformly is 210N.