what is the molality of 12.5 solvation of glucose i water?The molecular weight of glucose is 180.00

I don't know what solvation means, at least in the sense of the problem.

AND you gave no mass water.
AND you gave no units for the 12.5 WHAT?

To find the molality of a solute in a solution, you need to know the amount of solute in moles and the mass of the solvent in kilograms. In this case, the solute is glucose with a molecular weight of 180.00 g/mol, and the solvent is water.

First, convert the given mass of glucose (12.5 g) into moles. This can be done by dividing the mass by the molar mass:

Number of moles of glucose = mass of glucose / molar mass of glucose

Number of moles of glucose = 12.5 g / 180.00 g/mol

Next, find the mass of the water solvent in kilograms. To do this, divide the given mass of glucose by 1000 to convert it from grams to kilograms:

Mass of water = mass of glucose / 1000

Mass of water = 12.5 g / 1000 kg/g

Now that you have the number of moles of glucose and the mass of water in kilograms, you can calculate the molality:

Molality = moles of solute / mass of solvent in kg

Molality = (12.5 g / 180.00 g/mol) / (12.5 g / 1000 kg/g)

Molality = (12.5 g / 180.00 g/mol) / (12.5 g / 1000)

Simplifying the units:

Molality = (12.5 / 180.00) / (12.5 / 1000)

Molality = (12.5 / 180.00) * (1000 / 12.5)

Molality = 1000 / 180.00

Molality ≈ 5.56 mol/kg

Therefore, the molality of a 12.5 g solvation of glucose in water is approximately 5.56 mol/kg.