posted by Anonymous .
How many mL of 0.139 M KOH are needed to reach the equivalence point when 1.8 g of potassium hydrogen phthalate, KHP is titrated to a phenolphthalein end-point.
Write the equation and balance it.
Convert 1.8 g KHP to moles. moles = grams/molar mass
Convert moles KHP to moles NaOH using the coefficients in the balanced equation.
Finally, M NaOH = moles NaOH/L NaOH. Solve for L NaOH and convert to mL.
That's KOH and not NaOH.