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The voltaic cell:
Pt, H2(g, 1 atm), H+(xM),,H+ (1M), H2(g, 1 atm), Pt

registers an Ecell=+0.108 V. What is the pH of the soln?

I know that E*cell=0 for this. I was not sure if i place the [xM] on the top of the equation or the bottom of
Ecell=E*cell-0.0592/2*log[0.1M]/[xM]. If I do it with this equation, I get a pH of 2.64 and book says pH=2.82??? Thanks.

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