Write the net ionic equation for the reaction that occurs when aqueous solutions of barium hydroxide and hydrobromic acid are combined.
I know that the first part of the formula would be BaOH + HBr but I do not know what the product would be since HBr is one thing. I do not know what to do at this point. Please help. Thank you!
close but not quite.
Ba^2+ + 2OH^- + 2H^+ + 2Br^- ==> Ba^2+ + 2Br^- + 2H2O as the complete ionic equation. You can convert this to the NET ionic equation by canceling ions common to both sides; for example, Ba^2+ and Br^- appear on both sides so cancel them. That leaves
2OH^- + 2H^+ ==> 2H2O or
OH^-(aq) + H^+(aq) ==> H2O(l)
H+(aq)+OH-(aq)--->H2O(l)
H3O^+(aq)+OH^-(aq)-->2H2O
Ba(OH)2 + 2HBr ==> BaBr2 + 2H2O is the molecular equation. YOu can convert that to an ionic, then a net ionic equation. Remember that a base (Ba(OH)2) + an acid (HBr) produces a salt (BaBr2) + water.
thank you!
To write the net ionic equation for the reaction between barium hydroxide (Ba(OH)2) and hydrobromic acid (HBr), you need to first identify the soluble compounds and the insoluble compound formed as a result of the reaction.
In this case, barium hydroxide (Ba(OH)2) is a strong base and hydrobromic acid (HBr) is a strong acid. When a strong acid reacts with a strong base, they undergo a neutralization reaction, resulting in the formation of a salt and water.
The balanced chemical equation for the reaction is:
Ba(OH)2 + 2HBr → BaBr2 + 2H2O
Now, let's write the complete ionic equation by separating the soluble compounds into their ions:
Ba^2+ + 2OH^- + 2H^+ + 2Br^- → Ba^2+ + 2Br^- + 2H2O
In the complete ionic equation, the Ba^2+ and Br^- ions are on both sides of the equation, and they are spectator ions (ions that do not participate in the actual reaction and remain unchanged). Therefore, we can eliminate these spectator ions to write the net ionic equation:
2OH^- + 2H^+ → 2H2O
The net ionic equation shows only the species that actually react, excluding the spectator ions.
So, the net ionic equation for the reaction between barium hydroxide and hydrobromic acid is:
2OH^- + 2H^+ → 2H2O
Would this be correct for the complete equation?
Ba^2+ + OH^- + H^+ + Br^- = Ba^2+ + Br^- + H2O