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An airplane flies 137 km due west from city A to city B and then 412 km in the direction of 46.5◦ north of west from city B to city C. What is the distance between city A and
city C?
Relative to city A, in what direction is city C? Answer with respect to due east, with the counter-clockwise direction positive, within the limits of −180◦ to +180◦.

  • Physics -

    V1 = (137km,180deg.).
    V2 = (412km,133.5deg.).

    1. X = hor. = 137cos180 + 412cos133.5 =
    -137 + (-283.6) = -420.6km.
    Y = ver. = 137sin180 + 412sin133.5 =
    0 + 298.9 = 298.9km.

    d = sqrt((-420.6)^2 + (298.9)^2=516km.
    from A to C.

    2. tanA = Y/X = 298.9 / -420.6=-0.7107.
    A = -35.4 deg.,Cw.
    A = -35.4 + 180 = 144.6 deg..CCw. =
    Direction from A to C.

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