Physics
posted by Louis .
A person walks 28.2◦ north of east for 3.33 km. Another person walks due north, then due east to arrive at the same location. How far due north would this person walk?

1. Draw a rectangle with the long sides hor.
2. Draw a diagonal from lower left corner to upper right corner. This is
the hyp.of the 2 rt.triangles formed.
3. Label the hyp. 3.33km. The angle it makes with the hor. is 28.2 deg.
4. Find the length of a short(ver.) side:
Y = 3.33*sin28.2 = 1.57km., due North.