Physics
posted by Louis .
A person walks 28.2◦ north of east for 3.33 km. Another person walks due north, then due east to arrive at the same location. How far due north would this person walk?

Physics 
Henry
1. Draw a rectangle with the long sides hor.
2. Draw a diagonal from lower left corner to upper right corner. This is
the hyp.of the 2 rt.triangles formed.
3. Label the hyp. 3.33km. The angle it makes with the hor. is 28.2 deg.
4. Find the length of a short(ver.) side:
Y = 3.33*sin28.2 = 1.57km., due North.
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