A particle moving with uniform acceleration in a straight line was first observed to be moving at 4.5 m/s. After 10 sec, it was moving at 6.8 m/s. What is its acceleration?
Divide the velocity change (+2.3 m/s) by the time interval (10 s).
0.23 m/s^2
To calculate the acceleration of the particle, we can use the formula:
acceleration (a) = change in velocity (Δv) / time interval (Δt)
Given:
Initial velocity (u) = 4.5 m/s
Final velocity (v) = 6.8 m/s
Time interval (Δt) = 10 sec
We can calculate the change in velocity (Δv) by subtracting the initial velocity from the final velocity:
Δv = v - u
Substituting the given values:
Δv = 6.8 m/s - 4.5 m/s
Δv = 2.3 m/s
Now we can calculate the acceleration:
a = Δv / Δt
Substituting the values:
a = 2.3 m/s / 10 sec
a = 0.23 m/s^2
Therefore, the acceleration of the particle is 0.23 m/s^2.
To find the acceleration of the particle, we can use the equation of motion that relates the initial velocity (u), final velocity (v), acceleration (a), and time (t):
v = u + at
Given data:
Initial velocity, u = 4.5 m/s
Final velocity, v = 6.8 m/s
Time, t = 10 s
We can rearrange the equation to solve for acceleration:
a = (v - u) / t
Substituting the given values:
a = (6.8 m/s - 4.5 m/s) / 10 s
Next, we can calculate the difference in velocity:
a = 2.3 m/s / 10 s
Finally, we can divide the difference in velocity by the time to find the acceleration:
a = 0.23 m/s²
Therefore, the acceleration of the particle is 0.23 m/s².