# chemistry 12

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Calculate [H3O] an [OH] for a sodium hydroxide solution having a pH of 12.5.

I'm having a hard time with this i'm not sure how to start it. Please help me!

• chemistry 12 -

I would start by converting pH to pOH.
pH + pOH = pKw = 14
Then solve for OH^= from
pOH = -log(OH^-)

Or you can go another way.
pH = -log(H^+) and solve for (H^+), then
(H^+)(OH^-) = Kw = 1E-14 and solve for OH^-

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