(3x^2+2x-3)-(x^2-2x+1)
would the answer be 2x^2+4x+4
or did I do something wrong
No, it would be 2x^2+4x-4
(3x^2+2x-3)-(x^2-2x+1) =
3x^2 + 2x -3 - x^2 +2x -1 =
3x^2 - x^2 + 2x + 2x -3 -1 =
2x^2 + 4x - 4
To simplify the given expression (3x^2 + 2x - 3) - (x^2 - 2x + 1), you need to distribute the negative sign to each term inside the parentheses.
Distributing the negative sign, the expression becomes:
3x^2 + 2x - 3 - x^2 + 2x - 1
Now, combine like terms:
(3x^2 - x^2) + (2x + 2x) + (-3 - 1)
Simplifying further:
2x^2 + 4x - 4
So, the correct answer is 2x^2 + 4x - 4.