physics

posted by .

HOW DO YOU SOLVE FOR COS THETA. I KEEP GETTING ERROR.

  • physics -

    The number you are putting in the calculator is wrong. Check your calculations.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. algebra

    Can someone please help me do this problem?
  2. Math - Solving for Trig Equations

    For the following equation, why cannot I not solve it?
  3. Calculus

    I wanted to confirm that I solved these problems correctly (we had to convert the polar curves to Cartesian equations). 1.rcos(theta)=1 x=1 2.r=2*sin(theta)+2*cos(theta) r^2=2rsin(theta)+2rcos(theta) x^2+y^2=2y+2x (a little unsure …
  4. physics (the algebra bit)

    ok my question I'm trying to solve this for a m1 a = m2 g - m2 a - m1 g sin theta - (Mu kinetic)m1 g cos theta my text book gives me this a = (m1 + m2)^-1 (m2 g - m1 g sin theta - (Mu kinetic) m1 g cos theta) ok I don't see how I get …
  5. Physics

    An object is shot at 20m/s at an angle theta. The object lands 24m away. What is the angle?
  6. Physics - Inelastic Collision ( check + help)

    A billiard ball of mass 0.55kg moves with a velocity of 12.5m/s towards a stationary billiard ball of the identical mass and strikes it with a glancing blow. The first billiard ball moves of at an angle of 29.7deg clockwise from its …
  7. Trigonometry

    Okay, I have been given a trigonometric equation to solve (sin^2(theta) + cos(theta) = 2). So far, I have been able to use the Pythagorean identity to get (-cos^2(theta) + cos(theta) - 1 = 0), which I then multiplied by -1 on both …
  8. Precalculus 2

    Similiarly to a question I asked previously I took the same approach. the problem is: what value(s) of theta solve the following equation?
  9. Trigonometry

    Thank you STEVE!!!!! Suppose that Cos (theta) = 1/square root 2 if 0<equal to theta , pi/2 then sin(theta) = tan (theta) = If 3pi/2 less than equal to theta , 2pi then sin(theta) = tan (theta) = I know the trig functions but I feel …
  10. Trigonometry

    Solve the equation for solutions in the interval 0<=theta<2pi Problem 1. 3cot^2-4csc=1 My attempt: 3(cos^2/sin^2)-4/sin=1 3(cos^2/sin^2) - 4sin/sin^2 = 1 3cos^2 -4sin =sin^2 3cos^2-(1-cos^2) =4sin 4cos^2 -1 =4sin Cos^2 - sin=1/4 …

More Similar Questions