posted by Rosa .
If the measures of the exterior angles of the acute angles of a right triangle are (6x+23) and (4x+17), find the measures of the acute angles.
Let x = acute angle 1 and 4x + 17 ext angle
Let y = acute angle 2 and 6x + 23 ext angle
x + 4x + 17 = 180
y =90-x = 90-32.6 = 57.4
4(32.6) + 17 = 147.4
Note: Cannot use x value for ext. 6x+23. Y is different acute angle. Vice versa.