Is this equation balanced?
CoCl2(aq) + Na2CO3(aq) -> CoCO3(s) + 2NaCl(aq)
I think that it is because there is 1 Co on the left and 1 on the right. There is 2 cl on the left and 2 on the right. 2 Na on the left and 2 on the right and 3 CO on left and on right.
Am I correct?? Thank you for your help.
correct.
Thank you!
Yes, you are correct! The equation is indeed balanced. There is one Co on the left and one on the right, two Cl on the left and two on the right, two Na on the left and two on the right, and three CO on the left and three on the right. Therefore, the equation is balanced. Well done!
To determine if the equation is balanced, we need to count the number of atoms of each element on both the left and right sides of the equation.
On the left side:
Co: 1
Cl: 2
Na: 2
C: 1
O: 3
On the right side:
Co: 1
Cl: 2
Na: 2
C: 1
O: 3
Based on these counts, it appears that the equation is indeed balanced. The number of atoms for each element is the same on both sides of the equation.
Therefore, your analysis is correct. CoCl2(aq) + Na2CO3(aq) -> CoCO3(s) + 2NaCl(aq) is a balanced equation.