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The driver of a 1350 kg car, initially traveling at 10.6 m/s, applies the brakes, bringing the car to rest in a distance of 15.0 m.

Find the net work done on the car.

Not sure how to set this problem up.

  • Physics -

    work= change in KE= 1/2 m 10.6^2

    There are harder ways.
    find the acceleration: Vf^2=Vi^2+2ad solve for a
    Then F=ma solve for force
    work= force*distance.

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