What isthe focus of the parabola y = (1/8)(x – 5)^2 - 3

If you are asking this question, you must have covered it somewhere. Just look up the formula:

If 4py = x^2 then the focus is p units from the vertex.

You have 4(2)y = (x-5)^2 - 24

So, the focus is 2 units from the vertex (5,-3), or (5,-1)