posted by Parker .
Solve sin ¥è = -0.204 for 90¨¬ < ¥è < 270¨¬. Give your answer to the nearest tenth of a degree.
we want θ such that sin θ = -0.204
sine is negative in the 3rd & 4th quadrants, so we will only have one answer between 90° and 270°
Arcsin .204 = 11.77°
so, we want 180° + 11.77° = 191.77°