posted by Nicole .
I can't figure out how to set up this problem...You have a large amount of 8.00 M stock solution. You need 1.80L of 3.00 M solution for an experiment. How would you prepare the desired solution without wasting any stock solution?
The amount of solute in 1L of 1.80M solution would be the same as that in 1.80/8.00L of the 8.00M solution.
So, take 0.225L of the 8M, and fill the flask to 1L.
Sorry. Got my numbers mixed up.
The ratio is 3/8.
The solute in 1L of 3M solution is the same as in 3/8L of 8M.
So, take 3/8*1.8 = 0.675L of the 8M solution, and fill the flask to 1.80L