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What is the pH of a solution prpared by mixing 50.0 ml of .200 M HCLO4 with 10.0 ml of .100 M KOH

  • chemistry -

    HClO4 + KOH ==> KClO4 + H2O
    moles HClO4 = M x L = ?
    moles KOH = M x L = ?

    The reagent with the larger number of moles will be the one remaining. That reagent will be M = moles/total L soln and convert to pH from there.

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