How much 1,2-dibromocyclohexane should be obtained by adding bromine in carbon tetrachloride to 1g of cyclohexene

moles cyclohexane = grams/molar mass

moles 1,2-dibromohexane will be the same.
g 1,2-dibromohexane = moles x molar mass at 100% yield.

thanks DrBob222

To determine the amount of 1,2-dibromocyclohexane that would be obtained, we need to consider the reaction between bromine and cyclohexene.

The reaction involves the addition of bromine across the double bond of cyclohexene, resulting in the formation of 1,2-dibromocyclohexane. This is a 1:1 stoichiometric reaction, meaning that one mole of cyclohexene reacts with one mole of bromine to form one mole of 1,2-dibromocyclohexane.

First, we need to calculate the number of moles of cyclohexene in 1 gram. To do this, we need to know the molar mass of cyclohexene. The molar mass of cyclohexene is approximately 82.14 g/mol.

Number of moles of cyclohexene = mass of cyclohexene / molar mass of cyclohexene
= 1 g / 82.14 g/mol
≈ 0.0122 mol

Since the reaction is 1:1 stoichiometric, the number of moles of 1,2-dibromocyclohexane produced will be equal to the number of moles of cyclohexene. Therefore, the amount of 1,2-dibromocyclohexane obtained would also be approximately 0.0122 mol.

To convert moles to grams, we will need the molar mass of 1,2-dibromocyclohexane, which is approximately 215.87 g/mol.

Mass of 1,2-dibromocyclohexane = number of moles of 1,2-dibromocyclohexane * molar mass of 1,2-dibromocyclohexane
= 0.0122 mol * 215.87 g/mol
≈ 2.63 g

Therefore, approximately 2.63 grams of 1,2-dibromocyclohexane would be obtained by adding bromine in carbon tetrachloride to 1 gram of cyclohexene.