Silver nitrate (AgNO3) reacts with sodium
chloride as indicated by the equation
AgNO3 + NaCl ! AgCl + NaNO3 .
Howmany grams of NaCl would be required
to react with 518 mL of 0.543 M AgNO3
solution?
Answer in units of grams
16.43, found the answer
Idek
To determine the number of grams of NaCl required, we need to use the molarity and volume of the AgNO3 solution and the balanced chemical equation. Here is the step-by-step calculation:
1. Convert the given volume of AgNO3 solution to liters:
518 mL = 518/1000 = 0.518 L
2. Calculate the number of moles of AgNO3 using the molarity and volume:
Moles of AgNO3 = Molarity × Volume
= 0.543 M × 0.518 L
= 0.2817 mol
3. Use the stoichiometry of the balanced equation to determine the mole ratio of AgNO3 to NaCl. From the balanced equation, we can see that 1 mole of AgNO3 reacts with 1 mole of NaCl.
4. Since the mole ratio is 1:1, the number of moles of NaCl required is also 0.2817 mol.
5. Convert the moles of NaCl to grams using the molar mass of NaCl:
Molar mass of NaCl = 22.99 g/mol (sodium) + 35.45 g/mol (chlorine)
= 58.44 g/mol
Mass of NaCl = Moles of NaCl × Molar mass of NaCl
= 0.2817 mol × 58.44 g/mol
= 16.45 grams
Therefore, 16.45 grams of NaCl would be required to react with 518 mL of 0.543 M AgNO3 solution.
To calculate the grams of NaCl required to react with the AgNO3 solution, we can follow these steps:
Step 1: Calculate the number of moles of AgNO3.
Given that the volume of the AgNO3 solution is 518 mL (milliliters) and the concentration is 0.543 M (moles per liter), we can calculate the number of moles of AgNO3 using the formula:
moles = concentration (M) x volume (L)
Converting the volume to liters:
518 mL = 518/1000 L = 0.518 L
Now, we can calculate the moles of AgNO3:
moles of AgNO3 = 0.543 M x 0.518 L
Step 2: Determine the stoichiometry between AgNO3 and NaCl.
Looking at the balanced chemical equation:
AgNO3 + NaCl → AgCl + NaNO3
We can see that the ratio is 1:1 between AgNO3 and NaCl. This means that 1 mole of AgNO3 reacts with 1 mole of NaCl.
Step 3: Calculate the grams of NaCl.
Since we have calculated the moles of AgNO3 in Step 1, we can use that value to determine the moles and grams of NaCl required.
moles of NaCl = moles of AgNO3
Finally, to convert the moles of NaCl to grams, we need to multiply by its molar mass. The molar mass of NaCl is approximately 58.44 g/mol.
grams of NaCl = moles of NaCl x molar mass of NaCl
Now, you can perform the calculations to find the grams of NaCl required.