posted by Monique .
For each precipitation reaction, calculate how many grams of the first reactant are necessary to completely react with 17.3 g of the second reactant.
2KI(aq) + Pb(NO3)2(aq)--->PbI2(s) + 2KNO3(aq)
Not looking for the answer I really want to know if I did it correctly
17.3g Pb(NO3)/331.22gPb(NO3) x 2 mol KI x 166g KI = 17.3G KI
It looks ok to me including the answer.