the weight of a solid is 80g in air and 50g in liquid of relative density 1.5. calculate the relative density of the solid.
Loss of weight if solid in liquid = 50g- 30 g = 20g
Weight of equal volune of liquid by archimedes principle = 20 g
If the water displaced has a volume of V cm³ , then its weight= V×1.5 = 30 g
=》V= 20 cm³
Since , solid is completely immersed in the liquid , so volume of same solid = V
Therefore , The volume of water will be displaced by same solid = 20 cm³
Therefore , weight this displaced water =20 g
So we have specific gravity of solid = weight of solid in air / weight of water displaced = 80 g/ 20 g = 4
Hence , the relative density of the solid is 4.
To calculate the relative density of the solid, we need to compare its weight in air to its weight in the liquid.
The weight of the solid in air is 80g, and its weight in the liquid is 50g. We can use these values to find the relative density.
The relative density is defined as the ratio of the weight of the solid in air to the difference between its weight in air and its weight in the liquid.
Relative density = (Weight in air) / (Weight in air - Weight in liquid)
Substituting the given values:
Relative density = 80g / (80g - 50g)
Simplifying the equation:
Relative density = 80g / 30g
Calculating the relative density:
Relative density = 2.67
Therefore, the relative density of the solid is 2.67.
To calculate the relative density of the solid, we can use the equation:
Relative Density = Weight of Solid in Air / (Weight of Solid in Air - Weight of Solid in Liquid)
Given that the weight of the solid in air is 80g and the weight of the solid in the liquid is 50g, we can substitute these values into the equation:
Relative Density = 80g / (80g - 50g)
Relative Density = 80g / 30g
Relative Density = 2.67
Therefore, the relative density of the solid is approximately 2.67.