How many grams of PbCO3 will dissolve when exactly 5.0 L of 1.25 M H is added to 6.0 g of PbCO3?
When the equation is PbCO3(s) + 2H(+)(aq) = Pb(2+)(aq) + H2O(l) + CO2(g)
the solubility of Kl is 50g in 100g of H2O at 20 celcius, if 110g of Kl are added to 220g of H2O, is the soultion saturated or unsaturated?
and what is the %m/m of the solution?
To determine how many grams of PbCO3 will dissolve when 5.0 L of 1.25 M HCl is added to 6.0 g of PbCO3, we need to use stoichiometry to calculate the limiting reactant and the maximum amount of PbCO3 that can dissolve.
Step 1: Calculate the number of moles of HCl:
To find the number of moles of HCl, we use the formula: moles = concentration × volume.
moles of HCl = 1.25 M × 5.0 L = 6.25 moles of HCl
Step 2: Calculate the number of moles of PbCO3:
To calculate the number of moles of PbCO3, we use the formula: moles = mass / molar mass.
The molar mass of PbCO3 (lead carbonate) is:
(Pb: 207.2 g/mol) + (C: 12.01 g/mol) + 3(O: 16.00 g/mol) = 267.21 g/mol
moles of PbCO3 = 6.0 g / 267.21 g/mol = 0.0224 moles of PbCO3
Step 3: Use the balanced equation to determine the stoichiometry of the reaction:
From the balanced equation, we know that 1 mole of PbCO3 reacts with 2 moles of HCl to produce 1 mole of Pb(2+).
Step 4: Determine the limiting reactant:
The limiting reactant is the reactant that is completely consumed and determines the maximum amount of product that can be formed. To find the limiting reactant, we compare the moles of HCl and PbCO3.
Moles of HCl: 6.25 moles
Moles of PbCO3: 0.0224 moles
Since the PbCO3 has fewer moles than HCl, it is the limiting reactant.
Step 5: Calculate the maximum amount of PbCO3 that can dissolve:
Since PbCO3 is the limiting reactant, we use its moles to calculate the maximum amount that can dissolve.
grams of PbCO3 = moles of PbCO3 × molar mass of PbCO3
grams of PbCO3 = 0.0224 moles × 267.21 g/mol ≈ 5.98 g
Therefore, when exactly 5.0 L of 1.25 M HCl is added to 6.0 g of PbCO3, approximately 5.98 grams of PbCO3 will dissolve.
Is this anything more than a stoichiometry problem? I don't think so.
Here is a set of directions for working stoichiometry problems. M x L = moles. Convert moles H^+ to moles Pb^2+ and convert to grams PbCO3.
http://www.jiskha.com/science/chemistry/stoichiometry.html