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Set up an equation, which when solved will give the points where the tangent line has y-intercept 5.

  • calculus -

    f' = a = -8(2x+1)/(x^2+x+2)^2

    y = a x + 5

    8/(x^2+x+2) = -8(2x^2+x)/ (x^2+x+2)^2 + 5

  • calculus -

    Damon, so what you did was apply the quotient rule to the ax part? Wouldn't the -8 be -8x then? And if I'm doing it right, would my final equation be this?

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