# calculus

posted by .

f(x)=8/(x^2+x+2)
Set up an equation, which when solved will give the points where the tangent line has y-intercept 5.

• calculus -

f' = a = -8(2x+1)/(x^2+x+2)^2

y = a x + 5

8/(x^2+x+2) = -8(2x^2+x)/ (x^2+x+2)^2 + 5
etc

• calculus -

Damon, so what you did was apply the quotient rule to the ax part? Wouldn't the -8 be -8x then? And if I'm doing it right, would my final equation be this?
0=(5x^4+10x^3+x^2+4x+4)/(x^2+x+2)^2

## Similar Questions

1. ### secant line, tangent line

f(x) = sqrt(x-1), 1<=x<=3 Let A = (a,f(a)), and B = (b,f(b)). Write an equation for 1. the secant line AB 2. a tangent line to f in the interval (a,b) that is parallel to AB Thank you for all the help. For the line, you have …
2. ### Math

The graph of the equation y=4-x consists of all the points in the coordinate plane that satisfy the equation. List 5 points that satisfy y= 4-x. Also, what do you think is the minimum number of points you need to plot in order to draw …
3. ### Algebra

Given a line containing the points(1,4), (2,7) and (3,10) determine that slope-intercept form of the equation, provide one additional point on this line, and graph the funtion. Start by putting the first point into point-slope form: …
4. ### Math--Calculus

Let y = f(x) be the continuous function that satisfies the equation x^4 - (5x^2)(y^2) + 4y^4 = 0 and whose graph contains the points (2,1) and (2,2). Let L be the line tangent to the graph of f at x = 2. (a) Find and expression for …
5. ### math

i have more than one question so if u no any of the answers please tell me 1.) write the point-slope form of the equation of the line with slope -2 passing through the point ( -5, -9). 2.) write the point-slope form of an equation …
6. ### calculus

Determine the equation of the tangent line at the indicated -coordinate f(x)=e^(-2x)*in(8x) for x=2 The equation of the tangent line in slope-intercept form is y= ?
7. ### Calculus

Determine the equation of the tangent line at the indicated -coordinate. f(x) = e^(-0.4x) * ln(18x) for x= 3 The equation of the tangent line in slope-intercept form is
8. ### Calculus

1) An equation of the line contains points (7/9, 7) and (-7/9) is 2) Find the slope of the line tangent to the curve y=x^2 at the point (-0.6, 0.36) and find the corresponding equation of the tangent line
9. ### Calculus

Can someone show how this question is solved. Consider the curve given by the equation 2y^3 + y^2 - y^5 = x^4 -2x^3 +x^2 Find all points at which the tangent line to the curve is horizontal or vertical. Thanks!