The Earth rotates on its own axis once per day (24.0h). What is the tangential speed of the summit of Mt. Kilimanjaro (elevation 5895 m above sea level), which is located approximately on the equator, due to rotation of the Earth? The equatorial radius of Earth is 6378 km.

The distance of the Kilimanjaro summit from the axis of the Earth is

R = 6378 + 5.9 = ___ km

Multiply that by the angular rotation velocity of the Earth in radians/sec and you will have the tangential velocity.

Actually, the earth rotates 360 degrees (2 pi radians) in 23.93 hr = 86,148 s, not 24.0 hr. Your teacher may not realize this.

To find the tangential speed of the summit of Mount Kilimanjaro, we can use the formula:

v = rω

where:
v is the tangential speed,
r is the distance from the axis of rotation (equatorial radius of Earth + elevation of Kilimanjaro),
ω is the angular speed (which is equal to 2π radians per 24 hours).

First, let's convert the elevation of Mount Kilimanjaro from meters to kilometers:
5895 m = 5.895 km

Now, let's calculate the distance from the axis of rotation, r:
r = equatorial radius of Earth + elevation of Kilimanjaro
r = 6378 km + 5.895 km
r ≈ 6383.895 km

Next, let's calculate the angular speed, ω:
ω = 2π radians / 24 hours
ω ≈ 0.2618 radians per hour

Finally, let's substitute the values into the formula to find the tangential speed, v:
v = rω
v ≈ 6383.895 km * 0.2618 radians per hour
v ≈ 1672.286 km/h

Therefore, the tangential speed of the summit of Mount Kilimanjaro due to the rotation of the Earth is approximately 1672.286 km/h.

To calculate the tangential speed of the summit of Mount Kilimanjaro due to the rotation of the Earth, we need to find the circumference of the circle traced by the summit as the Earth rotates.

The Earth completes one rotation in 24.0 hours, so the time taken for one rotation is 24.0 x 60 x 60 seconds = 86,400 seconds.

The radius of the Earth at the equator is given as 6378 km, but we need to convert it to meters by multiplying by 1000. So the equatorial radius of the Earth is 6378 km x 1000 = 6,378,000 meters.

Now, we can calculate the circumference of the Earth at the equator using the formula:

Circumference = 2 x π x radius

Circumference = 2 x 3.14159 x 6,378,000 meters = 40,075,592 meters.

Since the Earth completes one rotation in 86,400 seconds, the tangential speed of the summit of Mount Kilimanjaro is:

Tangential Speed = Circumference / Time taken

Tangential Speed = 40,075,592 meters / 86,400 seconds ≈ 463.83 meters per second.

Therefore, the tangential speed of the summit of Mount Kilimanjaro, located approximately on the equator, due to the rotation of the Earth is approximately 463.83 meters per second.